In this paper, we prove that if $\mathcal{A}=\{E_i\}_{i=1}^{n}$ is a finite
commutative quantum measurement, then the fixed points set of L\"{u}ders
operation $L_{{\cal A}}$ is the commutant ${\cal A}'$ of ${\cal A}$, the result
answers an open problem partially. We also give a concrete example of a
L\"{u}ders operation $L_{{\cal A}}$ with $n=3$ such that $L_{{\cal A}}(B)=B$
does not imply that the quantum effect $B$ commutes with all $E_1, E_2$ and
$E_3$, this example answers another open problem.
Let $H$ be a complex Hilbert space, ${\cal B}(H)$ be the set of bounded
linear operator on $H$, ${\cal E}(H)$ be the set of $\{A\in {\cal B}(H): 0\leq
A\leq I\}$, $1\leq n\leq\infty$, ${\cal A}=\{E_i\}_{i=1}^{n}\subseteq {\cal
E}(H)$ be commutative, $\Phi_{{\cal A}}$ be the completely positive map which
be defined by $\Phi_{{\cal A}}:{\cal B}(H)\longrightarrow {\cal B}(H):
B\longmapsto \sum\limits_n A_n B A_n^*$. In this paper, we prove the following
results: