Zhi-Wei Sun

  1. Super congruences and Euler numbers.

    Authors: Zhi-Wei Sun
    Subjects: Number Theory
    Abstract

    Let $p$ be an odd prime. We prove that
    $$\sum_{k=0}^{p-1}\binom{2k}{k}/2^k=(-1)^{(p-1)/2}-p^2E_{p-3} (mod p^3),$$
    where E_0,E_1,E_2,... are Euler numbers. We also determine
    $\sum_{k=0}^{p-1}\binom{2k}{k}^2/16^k$ mod $p^4$ and show that
    $$\sum_{k=0}^{(p-1)/2}(4k+1)\binom{2k}{k}^2/16^k=p^2(2^p-1) (mod p^4).$$ We
    formulate many conjectures concerning such super congruences and relate most of
    them to Euler numbers.

  2. On almost universal mixed sums of squares and triangular numbers.

    Authors: Zhi-Wei Sun, Ben Kane
    Subjects: Number Theory
    Abstract

    In 1997 Ken Ono and K. Soundararajan [Invent. Math. 130(1997)] proved that
    under the generalized Riemann hypothesis any positive odd integer greater than
    2719 can be represented by the famous Ramanujan form $x^2+y^2+10z^2$,
    equivalently the form $2x^2+5y^2+4T_z$ represents all integers greater than
    1359, where $T_z$ denotes the triangular number $z(z+1)/2$.

  3. On harmonic numbers and Lucas sequences.

    Authors: Zhi-Wei Sun
    Subjects: Number Theory
    Abstract

    Harmonic numbers $H_k=\sum_{0<j\le k}1/j (k=0,1,2,...)$ arise naturally in
    many fields of mathematics. In this paper we initiate the study of congruences
    involving both harmonic numbers and Lucas sequences. One of our three theorems
    is as follows: Let u_0=0, u_1=1, and u_{n+1}=u_n-4u_{n-1} for n=1,2,3,....
    Then, for any prime p>5 we have $$\sum_{k=0}^{p-1}u_{k+\delta}H_k/2^k=0 (mod
    p),$$ where $\delta=0$ if p=1,2,4,8 (mod 15), and $\delta=1$ otherwise.

  4. Curious congruences for Fibonacci numbers.

    Authors: Zhi-Wei Sun
    Subjects: Number Theory
    Abstract

    In this paper we establish some sophisticated congruences involving central
    binomial coefficients and Fibonacci numbers. For example, we show that if
    $p\not=2,5$ is a prime then
    $$\sum_{k=0}^{p-1}F_{2k}\binom{2k}{k}=(-1)^{[p/5]}(1-(p/5)) (mod p^2)$$ and
    $$\sum_{k=0}^{p-1}F_{2k+1}\binom{2k}k=(-1)^{[p/5]}(p/5) (mod p^2).$$ We also
    obtain similar results for some other second-order recurrences.

  5. Congruences involving binomial coefficients and Lucas sequences.

    Authors: Zhi-Wei Sun
    Subjects: Number Theory
    Abstract

    In this paper we obtain some congruences involving central binomial
    coefficients and Lucas sequences.We also raise several conjectures.

  6. Open Conjectures on Congruences.

    Authors: Zhi-Wei Sun
    Subjects: Number Theory
    Abstract

    We collect here various conjectures on congruences made by the author in a
    series of papers, some of which involve binary quadratic forms and other
    advanced theories. Part A consists of unsolved conjectures of the author while
    conjectures in Part B have been recently confirmed. We hope that this material
    will interest number theorists and stimulate further research. Number theorists
    are welcome to work on those open conjectures.

  7. Arithmetic theory of harmonic numbers.

    Authors: Zhi-Wei Sun
    Subjects: Number Theory
    Abstract

    Harmonic numbers $H_k=\sum_{0<j<=k}1/j (k=0,1,2,...)$ play important roles in
    mathematics. In this paper we investigate their arithmetic properties and
    obtain various basic congruences. Let p>3 be a prime. We show that

    $$\sum_{k=1}^{p-1}H_k/(k2^k)=0 (mod p), \sum_{k=1}^{p-1}H_k^2=2p-2 (mod p^2),
    \sum_{k=1}^{p-1}H_k^3=6 (mod p),$$ and $$\sum_{k=1}^{p-1}H_k^2/k^2=0 (mod p)
    provided p>5.$$ Our tools include some sophisticated combinatorial identities
    and properties of Bernoulli numbers.

  8. On congruences related to central binomial coefficients.

    Authors: Zhi-Wei Sun
    Subjects: Number Theory
    Abstract

    In this paper we obtain several congruences modulo an odd prime p which are
    related to central binomial coefficients. For example,
    $$\sum_{k=0}^{p-1}\binom{2k}{k}^3/64^k=\cases4x^2 (mod p)&if p=x^2+y^2 with x
    odd and y even, \\0 (mod p)& if p=3 (mod 4);$$ and
    $$\sum_{k=0}^{p-1}C_k^2}/16^k=-3 (mod p) and \sum_{k=0}^{p-1}C_k^3/64^k=7 (mod
    p),$$ where $C_k$ denotes the Catalan number $\binom{2k}{k}/(k+1)$. We also
    pose several challenging conjectures one of which states that if p=3,5,6 (mod
    7)$ then $$\sum_{k=0}^{p-1}\binom{2k}{k}^3=0 (mod p^2).$$

  9. On sums of binomial coefficients modulo p^2.

    Authors: Zhi-Wei Sun
    Subjects: Number Theory
    Abstract

    Let p be an odd prime and let a be a positive integer. In this paper we
    investigate the sum $\sum_{k=0}^{p^a-1}\binom{hp^a-1}{k}\binom{2k}{k}/m^k$ mod
    p^2, where h,m are p-adic integers with m\not=0 (mod p). For example, we show
    that if h(2h-1)\not=0 (mod p) then $$
    sum_{k=0}^{p^a-1}\binom{hp^a-1}{k}\binom{2k}{k}(-h/2)^k
    =(\frac{1-2h}{p^a})(1+h((4h-2)^{p-1}/h^{p-1}-1)) (mod p^2),$$ where (-) denotes
    the Jacobi symbol.

  10. Proof of two conjectures on 3-adic valuations.

    Authors: Zhi-Wei Sun, Hao Pan
    Subjects: Number Theory
    Abstract

    Sun and Tauraso conjectured that for any positive integer $a$ we have
    $$\sum_{k=0}^{3^a-1}\binom{2k}{k}=0 (mod 3^{2a})$$ and furthermore
    $$3^{-2a}}\sum_{k=0}^{3^a-1}\binom{2k}k=1 (mod 3).$$ Recently a $q$-analogue of
    the first congruence was conjectured by Guo and Zeng. In this paper we prove
    both conjectures.

  11. Proof of two conjectures on 3-adic valuations.

    Authors: Zhi-Wei Sun, Hao Pan
    Subjects: Number Theory
    Abstract

    Sun and Tauraso conjectured that for any positive integer $a$ we have
    $$\sum_{k=0}^{3^a-1}\binom{2k}{k}=0 (mod 3^{2a})$$ and furthermore
    $$3^{-2a}}\sum_{k=0}^{3^a-1}\binom{2k}k=1 (mod 3).$$ Recently a $q$-analogue of
    the first congruence was conjectured by Guo and Zeng. In this paper we prove
    both conjectures.

  12. p-adic valuations of some sums of binomial coefficients.

    Authors: Zhi-Wei Sun
    Subjects: Number Theory
    Abstract

    Let $m$ and $n>0$ be integers. Suppose that $p$ is a prime dividing $m-4$ but
    not dividing $m$. We show that
    $$\nu_p(\sum_{k=0}^{n-1}\frac{\binom{2k}k}{m^k})$ is at least $\nu_p(n)$, where
    $\nu_p(x)$ denotes the $p$-adic valuation of $x$ at $p$. Furthermore, if
    $p\not=3$ or $3\nmid n$ then
    $$n^{-1}\sum_{k=0}^{n-1}\frac{\bi{2k}k}{m^k}=\frac{\binom{2n-1}{n-1}}{m^{n-1}}
    (mod p^{\nu_p(m-4)}).$$ This implies several conjectures of Guo and Zeng [GZ].

  13. p-adic valuations of some sums of binomial coefficients.

    Authors: Zhi-Wei Sun
    Subjects: Number Theory
    Abstract

    Let $m$ and $n>0$ be integers. Suppose that $p$ is a prime dividing $m-4$ but
    not dividing $m$. We show that
    $$\nu_p(\sum_{k=0}^{n-1}\frac{\binom{2k}k}{m^k})$ is at least $\nu_p(n)$, where
    $\nu_p(x)$ denotes the $p$-adic valuation of $x$ at $p$. Furthermore, if
    $p\not=3$ or $3\nmid n$ then
    $$n^{-1}\sum_{k=0}^{n-1}\frac{\bi{2k}k}{m^k}=\frac{\binom{2n-1}{n-1}}{m^{n-1}}
    (mod p^{\nu_p(m-4)}).$$ This implies several conjectures of Guo and Zeng [GZ].

  14. New congruences for central binomial coefficients.

    Authors: Zhi-Wei Sun, Roberto Tauraso
    Subjects: Number Theory
    Abstract

    Let p be a prime and let a be a positive integer. In this paper we determine
    $\sum_{k=0}^{p^a-1}\binom{2k}{k+d}/m^k$ and
    $\sum_{k=1}^{p-1}\binom{2k}{k+d}/(km^{k-1})$ modulo $p$ for all d=0,...,p^a,
    where m is any integer not divisible by p. For example, we show that if
    $p\not=2,5$ then
    $$\sum_{k=1}^{p-1}(-1)^k\frac{\binom{2k}k}k=-5\frac{F_{p-(\frac p5)}}p (mod
    p),$$ where F_n is the n-th Fibonacci number and (-) is the Jacobi symbol. We
    also prove that if p>3 then $$\sum_{k=1}^{p-1}\frac{\binom{2k}k}k={8/9}
    p^2B_{p-3} (mod p^3),$$ where B_n denotes the n-th Bernoulli number.

  15. New congruences for central binomial coefficients.

    Authors: Zhi-Wei Sun, Roberto Tauraso
    Subjects: Number Theory
    Abstract

    Let p be a prime and let a be a positive integer. In this paper we determine
    $\sum_{k=0}^{p^a-1}\binom{2k}{k+d}/m^k$ and
    $\sum_{k=1}^{p-1}\binom{2k}{k+d}/(km^{k-1})$ modulo $p$ for all d=0,...,p^a,
    where m is any integer not divisible by p. For example, we show that if
    $p\not=2,5$ then
    $$\sum_{k=1}^{p-1}(-1)^k\frac{\binom{2k}k}k=-5\frac{F_{p-(\frac p5)}}p (mod
    p),$$ where F_n is the n-th Fibonacci number and (-) is the Jacobi symbol. We
    also prove that if p>3 then $$\sum_{k=1}^{p-1}\frac{\binom{2k}k}k={8/9}
    p^2B_{p-3} (mod p^3),$$ where B_n denotes the n-th Bernoulli number.

  16. On 2-adic orders of some binomial sums.

    Authors: Zhi-Wei Sun, Hao Pan
    Subjects: Combinatorics
    Abstract

    We prove that for any nonnegative integers $n$ and $r$ the binomial sum $$
    \sum_{k=-n}^n\binom{2n}{n-k}k^{2r} $$ is divisible by
    $2^{2n-\min\{\alpha(n),\alpha(r)\}}$, where $\alpha(n)$ denotes the number of
    1's in the binary expansion of $n$. This confirms a recent conjecture of Guo
    and Zeng.

  17. Some congruences for the second-order Catalan numbers.

    Authors: Zhi-Wei Sun, Li-Lu Zhao, Hao Pan
    Subjects: Number Theory
    Abstract

    Let p be any odd prime. We mainly show that
    $$\sum_{k=1}^{p-1}binomial(3k,k)*2^k/k=0 (mod p)$$ and
    $$\sum_{k=1}^{p-1}2^{k-1}C_k^{(2)}=(-1)^{(p-1)/2}-1 (mod p),$$ where
    $C_k^{(2)}=binomial(3k,k)/(2k+1)$ is the $k$th Catalan number of order 2.

  18. Some congruences for the second-order Catalan numbers.

    Authors: Zhi-Wei Sun, Li-Lu Zhao, Hao Pan
    Subjects: Number Theory
    Abstract

    Let p be any odd prime. We mainly show that
    $$\sum_{k=1}^{p-1}binomial(3k,k)*2^k/k=0 (mod p)$$ and
    $$\sum_{k=1}^{p-1}2^{k-1}C_k^{(2)}=(-1)^{(p-1)/2}-1 (mod p),$$ where
    $C_k^{(2)}=binomial(3k,k)/(2k+1)$ is the $k$th Catalan number of order 2.

  19. Various congruences involving binomial coefficients and higher-order Catalan numbers.

    Authors: Zhi-Wei Sun
    Subjects: Number Theory
    Abstract

    Let $p$ be a prime and let $a$ be a positive integer. In this paper we
    investigate $\sum_{k=0}^{p^a-1}\binom[(h+1)k,k+d]/m^k$ modulo a prime $p$,
    where $d$ and $m$ are integers with $-h<d<=p^a$ and $m\not=0 (mod p)$. We also
    study congruences involving higher-order Catalan numbers
    $C_k^{(h)}=\binom[(h+1)k,k]/(hk+1)$. Our tools include linear recurrences and
    the theory of cubic residues. Here are some typical results in the paper.

  20. Various congruences involving binomial coefficients and higher-order Catalan numbers.

    Authors: Zhi-Wei Sun
    Subjects: Number Theory
    Abstract

    Let $p$ be a prime and let $a$ be a positive integer. In this paper we
    investigate $\sum_{k=0}^{p^a-1}\binom[(h+1)k,k+d]/m^k$ modulo a prime $p$,
    where $d$ and $m$ are integers with $-h<d<=p^a$ and $m\not=0 (mod p)$. We also
    study congruences involving higher-order Catalan numbers
    $C_k^{(h)}=\binom[(h+1)k,k]/(hk+1)$. Our tools include linear recurrences and
    the theory of cubic residues. Here are some typical results in the paper.

  21. On universal sums of polygonal numbers.

    Authors: Zhi-Wei Sun
    Subjects: Number Theory
    Abstract

    For m=3,4,..., the polygonal numbers of order m are given by
    $p_m(n)=(m-2)n(n-1)/2+n (n=0,1,2,...)$. For positive integers $a,b,c$ and
    $i,j,k>2$ with max{i,j,k}>4, we call the triple $(ap_i,bp_j,cp_k)$ universal if
    for any n=0,1,2,... there are nonnegative integers $x,y,z$ such that
    $n=ap_i(x)+bp_j(y)+cp_k(z)$. We show that there are only 95 candidates for
    universal triples (two of which are $(p_4,p_5,p_6)$ and $(p_3,p_4,p_{27})$),
    and conjecture that they are indeed universal triples.

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